3sin^2(x)+sin(2x)-2=0

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Solution for 3sin^2(x)+sin(2x)-2=0 equation: 


Simplifying
3sin2(x) + sin(2x) + -2 = 0

Multiply in2s * x
3in2sx + sin(2x) + -2 = 0

Remove parenthesis around (2x)
3in2sx + ins * 2x + -2 = 0

Reorder the terms for easier multiplication:
3in2sx + 2ins * x + -2 = 0

Multiply ins * x
3in2sx + 2insx + -2 = 0

Reorder the terms:
-2 + 2insx + 3in2sx = 0

Solving
-2 + 2insx + 3in2sx = 0

Solving for variable 'i'.

Move all terms containing i to the left, all other terms to the right.

Add '2' to each side of the equation.
-2 + 2insx + 2 + 3in2sx = 0 + 2

Reorder the terms:
-2 + 2 + 2insx + 3in2sx = 0 + 2

Combine like terms: -2 + 2 = 0
0 + 2insx + 3in2sx = 0 + 2
2insx + 3in2sx = 0 + 2

Combine like terms: 0 + 2 = 2
2insx + 3in2sx = 2

Reorder the terms:
-2 + 2insx + 3in2sx = 2 + -2

Combine like terms: 2 + -2 = 0
-2 + 2insx + 3in2sx = 0

The solution to this equation could not be determined.

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